Hey! I have a function defined with default arguments like so: def my_func(arg1, arg2 \\ %{}, arg3 \\ false) I want to pass it as a variable, so I’m capturing it as &my_func/3. However, I want to be able to invoke it with only one or two arguments as well, but that gives an error saying “function …

Default arguments are just a syntactic sugar that transforms into functions with different arity: def my_func(arg1, arg2 \\ %{}, arg3 \\ false) # arg2 = %{} and arg3 = false def my_func(arg1) # arg3 = false def my_func(arg1, arg2) # no default arguments def my_func(arg1, arg2, arg3) So if you …

[image] D4no0: Default arguments are just a syntactic sugar that transforms into functions with different arity: Or in a bit other words. Default arguments simplify function definition, but they don’t change how functions are called or referenced. &my_func/3 captures the arity 3 version of th…

Got it, thanks. Is there a way to imitate this behaviour then? (without passing the arguments as a list or something like that)

Elixir Programming Language Forum

Capturing a function with default arguments?

Questions & Help Questions

LostKobrakai June 25, 2024, 9:30am 5

You can look into mfa tuples and apply.