I am currently trying to download a large file via HTTP streaming. That’s hard enough as the only examples I find usually involve a receive loop of some kind of receive loop. See the following example taken from this tutorial : defp async_response(conn, id) do :ok = :ibrowse.stream_next(id) …

I was going to try and do this, but my approach was wrong so I did a little digging and found this article: [image] Elixir Consulting and Web Development - Erlang Solutions Expert Business Growth Strategies. Boost efficiency & profits with our tailored solutions. Contact us now! …

Have a look at Stream.resource/3 . I’m not up on current http client features so don’t know if any include what you’re looking for.

I know about Stream.resource but have no idea how I can reconclie the receive loop with this. I’m wondering if anyone had a similar problem and has a working solution.

[image] amarraja: then setup stream resource to request the next chunks. The term stream is underspecified. The solution you are describing buffers data being pushed by HTTP onto the process which is captured via a receive loop so that it can wait in the buffer for a consumer to pull the data…

Thanks @peerreynders , that got me thinking. Unfortunately I read your reply a few times and I think I confused myself! So how would the original problem look as a push stream? I’m making the assumption that when a request is made to download a large file, the client just receives data as it comes …

[image] amarraja: the consumer will “pull” when ready. That isn’t entirely accurate. The consumer simply communicates that it is ready to have a certain amount data pushed to it - it doesn’t actively pull data. So the difference is: In a pull scenario the client can be blocked if no data i…

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Convert receive loop into Stream

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leifg December 18, 2018, 6:03pm 5

That looks exactly like what I am looking for, thank you so much!