I want to mimic ES6’s destructing assignment using Elixir’s sigil. What I want to achieve is ~m{foo bar} = %{foo: 1, bar: 2} foo #=> 1 bar #=> 2 So far I have the following code defmodule DestructingAssignment do defmacro __using__(_) do quote do: import unquote(__MODULE__) end defm…

I think just one small change is required: defmodule DestructingAssignment do defmacro __using__(_) do quote do: import unquote(__MODULE__) end defmacro sigil_m({:<<>>, _line, [string]}, []) do spec = string |> String.split |> Stream.map(&String.to_atom/1) …

Works like a charm! But here come a new question, what does the last part of an AST node mean?

Have a look at this: GitHub - whatyouhide/short_maps: ⚠️Retired⚠️ library that provided a ~m sigil for ES6-like map destructuring in Elixir. · GitHub

[image] Aetherus: Works like a charm! But here come a new question, what does the last part of an AST node mean? According to Saša Jurić’s article about macros , the third part of variable AST represents where the quoting happens. If it’s nil, the identifier is not hygienic. Check out paragrap…

I have no ideas how macros work, but this is very useful and I made a string version also: defmacro sigil_d({:<<>>, _line, [string]}, []) do spec = string |> String.split() |> Stream.map(&String.to_atom/1) # how could we do without this? |> Enum.map(&{to_string(&1), {&1…

Elixir Programming Language Forum

Destructing assignment

Questions & Help Questions

KristerV October 19, 2022, 8:23am 7

can’t edit.

this algo has served me well, but today i’d go for shorter_maps.