Can Someone please explain difference between anonymous and named functions ? where we need to use Anonynous and Named functions? From the Agents tutorial they use @doc “”" Gets a value from the bucket by key. “”" def get(bucket, key) do Agent.get(bucket, &Map.get(&1, key)) end in the ab…

an anonymous function is not attached to a module. example my_func = fn x → IO.puts x end and You call it like this my_func.(“yo”) Please note the dot Map.get is a named function

Is there Any particular reason to use named function Map.get/3 as anonymous function as &Map.get(&1, key)?

Passing a function is so usual, that there is this & &1 notation, but it does not mean that Map.get is anonymous. You can do like something like this with a more complex function do_what_you_want = fn x -> # do some stuff end map |> Enum.map(&do_what_you_want.(&1)) Otherwise, You should have done …

Thanks man , i found this stack page with more info, but i am not clear about This code will fail to compile because every time you see a def, you get an empty variable scope. That is an important difference between them what is mean by empty variable scope?

from this example x = 1 def hello(y) do x + y end after we declare def, do u mean that only y is bound to the scope of the function alone

iex(1)> a = 1 1 iex(2)> f = fn -> IO.puts a end #Function<...> iex(3)> f.() 1 :ok iex(4)> defmodule F do ...(4)> def g, do: IO.puts(a) ...(4)> end ** (CompileError) iex:5: function a/0 undefined ... stripped ... As you can see here, the defed function has no access to the a that was bound outside…

[image] kokolegorille: an anonymous function is not attached to a module. As a statement that is incorrect. An anonymous function is attached to the module that creates it [ source ]. Execution of the anonymous function will force the module that created it to load - and if that module cannot …

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Difference between anonymous and named functions?

Questions & Help Questions

NobbZ June 8, 2017, 11:02am 6

Well, simply that there are no variables bound in the scope.