Hello everyone, Here is some erlang code I wanted to translate to Elixir… here is a simple example in the console. $ erl Erlang/OTP 22 [erts-10.4.4] [source] [64-bit] [smp:8:8] [ds:8:8:10] [async-threads:1] [hipe] Eshell V10.4.4 (abort with ^G) 1> Pid=self(). <0.82.0> …

Elixir allows to rebind the variables, so this is perfectly possible to do: a = 1 a = 2 Which will then be translated to Erlang as a something like: A@1 = 1 A@2 = 2 To have the same behaviour as in Erlang, you need to use pin operator (^): a = 1 ^a = 2 # will fail with no match So in your case…

Thanks, I forgot the pin :slight_smile:

[image] kokolegorille: Why is that different? Erlang doesn’t distinguish between binding a value and pattern-matching on an already-bound value (part of its Prolog heritage IIRC). Elixir disambiguates between these two cases with the ^ operator, referred to as the “pin operator”: K…

Thanks, I need a :coffee: :slight_smile: This is the full function def on_exit(pid, fun) do spawn(fn -> ref = Process.monitor(pid) receive do {:DOWN, ^ref, :process, ^pid, reason} -> fun.(reason) end end) end

Elixir Programming Language Forum

Different closure between Erlang and Elixir

Questions & Help Questions

kokolegorille November 14, 2019, 1:00pm 3

Thanks, I forgot the pin