def func do convert_video.(1280) IO.puts(“Conversion done, starting to upload”) end I have this function, but problem is, if convert_video.(1280) takes too long, IO.puts(“Conversion done, starting to upload”) line does not execute, infact nothing after executes. However if convert_video.(1280) …

Also what you can do is register your process to give it a name: def func do Process.register(self(), :hello) convert_video.(1280) IO.puts("Conversion done, starting to upload") end Then start your app with iex (like iex -S mix phx.server if using Phoenix) and run a single long conversion (o…

Obvious question sorry but how are you sure that convert_video.(...) has finished?

it’s just calling a system command for ffmpeg, I can monitor the porgress as well as the process in the os, if they are still there. And I can see they are done. I also tried leaving it for more then an hour. It just does nothing. If I call other functions (via Phoenix api), it runs, even the same …

I am far from an expert but maybe ffmpeg does not send EOF to stdout (if that is even a thing…). Can you try with the rambo library?

That might be a case, trying that now. thank you ~

That was really helpful, Thank you very much ~ So, I found out, the process was returing nil after a while, then I realized it was the phoenix timeout after 60 seconds by default. So I increased the default timeout behaviour, and now it works. Alhamdulillah ~ Thanks again, May Allah return the fa…

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Elixir Programming Language Forum

Elixir function doesn't continue if takes too long

Questions & Help Questions

rvirding February 5, 2024, 5:05pm 6

A function always executes until it is completed.