Elixir v1.12.0-rc.0 released

Nope. That’ s equivalent to 1..n

FRom the docs:

Definition

An increasing range first..last//step is a range from first to last increasing by step where step must be a positive integer and all values v must be first <= v and v <= last. Therefore, a range 10..0//1 is an empty range because there is no value v that is 10 <= v and v <= 0.

Similarly, a decreasing range first..last//step is a range from first to last decreasing by step where step must be a negative integer and values v must be first >= v and v >= last. Therefore, a range 0..10//-1 is an empty range because there is no value v that is 0 >= v and v >= 10.