Nope. That’ s equivalent to 1..n
FRom the docs:
Definition
An increasing range
first..last//stepis a range fromfirsttolastincreasing bystepwherestepmust be a positive integer and all valuesvmust befirst <= v and v <= last. Therefore, a range10..0//1is an empty range because there is no valuevthat is10 <= v and v <= 0.Similarly, a decreasing range
first..last//stepis a range fromfirsttolastdecreasing bystepwherestepmust be a negative integer and valuesvmust befirst >= v and v >= last. Therefore, a range0..10//-1is an empty range because there is no valuevthat is0 >= v and v >= 10.






















