Is there any way to, at compile time overrid ALL functions foo that somebody would wrote in a module A. I think I can do it overriding def/2. But I feel like i would be using a hammer. Any ideas?

Using super. Sorry isn’t overload the word? Overrid is probably closer to what i think

Using super is the OO way to call parent object. That is not really working like this because there is no object in Elixir, just modules, functions and arguments. Composition is also preferred over inheritance… composition everywhere

@kokolegorille but if I have a funtion foo and juste want to overrid it, to print some log. Should i use something else than Kernel.super ?

You have to call super explicitly. But it seems as if you want to use something known as decorators. I’ve seen an experimental package for those years ago, not sure if it still works or is maintained. At least I remember it had problems with multi headed functions. The easiest is probably to simp…

Maybe like this def foo, do: ... def foo_with_log do log_here foo() end I know it’s not override like You want… but You can easily compose functions.

I’m not supposed to write anything in the module A. So a client would go: defmodule A do def foo, do: ... end and under the hood it would compile like defmodule A do def foo, do:stuff1 def foo, do:stuff2and stuff1 end And my main problem is that i don’t know the name and arity of fo…

Or better probably this def foo(x, y, z) do log_stuff(...) do_foo(x, y, z) end defp do_foo(...)... This way only the decorator is accessible and doesn’t have an obfuscated name.

You neither know how the function will be named nor what arguments it might get? What do you actually want to log then?

Elixir Programming Language Forum

Function overriding at compile time

Questions & Help Questions

homologist December 16, 2017, 1:19pm 11

The log was just an example. Its just some callbacks