Recursive function to iterate over a list

@CommandoSev it is a list acting as an accumulator. Here are some examples:

  1. Find out if something exists in a list:
list =  [1,2,3,4]

Enum.any?(list, fn item -> item == 3 end)
true

  1. If you want to get the item if it exists:
list =  [1,2,3,4]

Enum.find(list, fn item -> item == 3 end)
3

  1. If you want to find all of the matches and have them returned in a list:
list = [1, 2, 3, 4, 3]

# The second arg is the accumulator which I have named acc in the anonymous function
Enum.reduce(list, [], fn item, acc -> 
  # If true add the item to the acc list, otherwise return the acc as is
  if item == 3, do: [item | acc], else: acc  
end)
[3,3]

You can replicate the Enum.reduce function by writing your own recursive function:

list = [1, 2, 3, 4, 3]

# match on the empty list and return the accumulator
def my_reduce([], acc, _item), do: acc

# match on the head and tail of the list and test if item exists
def my_reduce([h | t], acc, item) do
acc = 
  if h == item do
   [h | acc] # add the matching item to the accumulator 
  else
   acc # no match so return acc as is
  end
 my_reduce(t, acc, item) # recursivly call my_reduce with the tail of the list and the acc
end

# start the recursive function by calling it
my_reduce(list, [], 3)

Hope this helps. If you tell us exactly what you are trying to do I am sure we can help work it out.

Andrew