Scenario I have a list I’m getting back where I have a mixture of letters and numbers as strings. I need the list to be sorted so it’s alphabetic first THEN numeric. # Sample data [ {"1",[]}, {"A",[]}, {"B",[]}, {"C",[]}, {"D",[]}, {"E",[]}, {"F",[]}, {"3",[]}, …

Using function proposed by @LostKobrakai : def sort(list), do: Enum.sort_by(list, &comparator/2) defp comparator(<<a, _::binary>> = ax, <<b, _::binary>> = bx) when a in ?0..?9 and b in ?0..9, do: ax <= bx defp comparator(<<a, _::binary>>, _) when a in ?0..?9, do: true defp comparator(ax, bx), do: a…

I’m getting this error when I copy and paste this into my Foo module. It looks like missing :do option in "defp" Also this syntax is foreign to me. Is this just saying that ‘b’ is expected to be a binary type? <<b, _::binary>>

No, this is pattern matching on binaries. We are getting out first byte and then ignoring the rest _ has type binary. More info Kernel.SpecialForms.<<>>

Elixir Programming Language Forum

Sorting a list alphabetic then numeric

Questions & Help Questions

LostKobrakai December 19, 2019, 3:00pm 2

Take a look at Enum.sort_by.