There seems to be no way to split an Enum like String.split does. Actually those functions have very different semantics. String.split("123045067809", "0") #=> ["123", "45", "678", "9"] function I’d like to have: l = [1,2,3,0,4,5,0,6,7,8,0,9] Enum.split(l, &(&1 == 0)) #=>[[1, 2, 3], [4, 5], [6, …

You can just pipe the chunk_by result like this: |> Enum.reject(&1 == [0])?

Actually, this is not that hard to write. Just def split(list, splitter, acc \\ []) def split([], _, []), do: [] def split([], _, acc), do: [:lists.reverse acc] def split([splitter | tail], splitter, acc) do [:lists.reverse(acc) | split(tail, splitter, [])] end def split([item | tail], splitter, …

Not much shorter, but using Enum instead of recursion: l = [1,2,3,0,4,5,0,6,7,8,0,9] Enum.chunk_while(l, [], fn 0, acc -> {:cont, Enum.reverse(acc), []} element, acc -> {:cont, [element | acc]} end, fn [] -> {:cont, []} acc -> {:cont, Enum.reverse(acc), []} end) # [[1, 2, 3], [4, 5], [6,…

Thats what I’m doing. Was just wondering why Enum does not do this and if s.o. else bothers.

The answer is probably in the question: because it’s fairly easy to assemble the desired solution and because it’s not preferable to devise a lot of list/stream combinators that can confuse people.

iex(2)> l |> Enum.join() |> String.split("0") ["123", "45", "678", "9"] :troll: Interesting though, especially as Enum.intersperse/2 exists.

[image] adamu: iex(2)> l |> Enum.join() |> String.split("0") ["123", "45", "678", "9"] :see_no_evil:

Here you go: defmodule Example do def sample(list) when is_list(list) do # we start with one empty list List.foldr(list, [[]], fn # in case we got 0 # we are adding new empty list at beginning of result 0, acc -> [[] | acc] # otherwise we are appending element …

Obligatory benchmarks. Name ips average deviation median 99th % recursion 3.98 M 251.49 ns ±11214.50% 188 ns 456 ns foldr 2.99 M 334.99 ns ±12387.85% 223 ns 506 ns reduce …

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String.split vs Enum.split_with

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Sebb September 23, 2022, 6:48am 8